The Tridecadal Korean (astralblue) wrote,
The Tridecadal Korean
astralblue

  • Mood:

Yay

2sin−1(sqrt(2+(1−P)cos(φ1+φ2)−(1+P)cos(φ1φ2))/2)

where P=cos(θ1θ2).

Phew.

Edit:

cos−1(cosφDcos2θA−cosφSsin2θA)

where φS=φ1+φ2, φD=φ1φ2 and θA=(θ2θ1)/2.

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